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求助,编写程序计算1到n之间的奇数和,并从键盘输...

//java写的import java.util.Scanner;public class OodSum {public static void main(String[] args) {Scanner sc = new Scanner(System.in);System.out.println("输入n的值:");int n = sc.nextInt();int sum = 0;for(int i = 1;i

Private Sub Command1_Click() Dim n As Integer Dim s As Double s = 0 n = Val(Text1.Text) For i = 1 To n If i Mod 2 = 1 Then s = s + i Next i Text3.Text = sEnd SubPrivate Sub Command2_Click() Dim n As Integer Dim s As Double s = ...

望采纳! #include void main() { int i,n; int result1=0,result2=0; printf("请输入n:"); scanf("%d",&n); for(i=0; i

//#include "stdafx.h"//If the vc++6.0, with this line.#include using namespace std;int main(int argc,char *argv[]){ int n,i,s; cout > n) || n

#include int main(){ int sum = 0; int n,i; scanf("%d",&n); for(i=0;i

C?还是? 捕获按键N代码略 int i; int sum=0; for (i=0;i

分解为两个素数之和的形?不是很明白,楼主举个例子吧。 看看我这个程序符不符合你的意思。 /*用c语言编程从键盘输入一个较大正整数n(n>=6), 并验证从6到n之间的所有偶数都可以分解为两个素数之和的形 */ #include #include #define N 500//定义...

C可以这么写: #include "stdio.h"int main(void){ int n; while(1){ printf("Input n(int n>0)...\nn="); if(scanf("%d",&n) && n>0){ n-=!(n&1); printf("The result is %d\n",(1+n)/2*(n/2+1)); break; } printf("Error, must be n>0: "); ff...

#include #include int ss(int n) /*检查n是否为素数,如果是则返回1,否则返回0*/ { int i; if(n

#include main() { int n,sum=0,i,m=0,j; printf("Input n:"); scanf("%d",&n); if(n==1) sum=0; else if(n==2) sum=2; else { sum=2; for(i=3;i

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