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用C语言 编写问题: 计算1~N之间所有奇数之和(简...

#include int main(){ int sum = 0; int n,i; scanf("%d",&n); for(i=0;i

odd=0;even=0; for(int i=1;i

#include int main() { int i,sum=0; printf("%d\n",100/2/2*100); // 按照 100内50个奇数 50个奇数又可以 变成 (1+99)(3+97)这样 for (i=1;i

1方法(1)使用一个计数器来判断终止条件(2)用除以2后的余数来判断奇偶2代码#includeintmain(){intcount,sumEven,sumOdd;count=sumEven=sumOdd=0;while(++count

望采纳! #include void main() { int i,n; int result1=0,result2=0; printf("请输入n:"); scanf("%d",&n); for(i=0; i

因为你没说用什么语言实现,所以我就用个C语言实现了 #include int main(){ int n,sum=0; scanf("%d", &n); for (int i=1; i

Private Sub Command1_Click() Dim n As Integer Dim s As Double s = 0 n = Val(Text1.Text) For i = 1 To n If i Mod 2 = 1 Then s = s + i Next i Text3.Text = sEnd SubPrivate Sub Command2_Click() Dim n As Integer Dim s As Double s = ...

根据偶数与奇数相间连续的特点,用一个for循环,省去偶数判断,直接从小于等于n的最大偶数开始减2相加到2即可。举例代码如下: #include "stdio.h"int main(int argc,char *argv[]){int n,s;printf("Input n(int n>0)...\nn=");if(scanf("%d",&n...

//java写的import java.util.Scanner;public class OodSum {public static void main(String[] args) {Scanner sc = new Scanner(System.in);System.out.println("输入n的值:");int n = sc.nextInt();int sum = 0;for(int i = 1;i

#include int isprime(int k) { int i; for(i=2;i*i

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